The iOS 10.3.3 jailbreak exploit has been announced under development, confirming a root can now support Apple devices like iPhone 6s, iPad mini 4 and iPod touch, among others.
German developer known as Siguza took Twitter on Tuesday, December 7 to announce that he was able to get root so far for iOS 10.3.3 jailbreak. At the moment, he is working on an exploit for iOS devices, which he called "v0rtex".
Also read: Microsoft Lumia user? You can now jailbreak any Windows Phone!
On his GitHub page for v0rtex, Siguza states the iOS 10.3.3 root exploit supports devices running on A7, A8 and A9 chips. These include iPhone 6, iPhone 6s Plus, iPhone SE, iPad (2017), iPhone 6, iPhone 6 Plus, 6th generation iPod touch, iPad mini 4, iPhone 5s, iPad Air, iPad mini 3 and iPad mini 2.
Siguza has been honest to divulge that the root has some considerable amount of issues at the moment and that he has to do with it. The developer has noted that he is unsure where this development is headed but assures the community that everything is "certainly not done yet".
He has added that he "might also do a write-up at some point, once [the root exploit is] fully working".
<=10.3.3 exploit, work in progress (gets root so far)https://t.co/22UzxRAhPV
— Siguza (@s1guza) December 6, 2017
Some fans in the meantime cannot hide their excitement for this development. Some throw a question which devices can this be available. Unfortunately, for iPhone 7 and newer devices will not be eligible once this root goes out in full swing.
*rubs hands +
— raymond sebastian (@RaymondSebas) December 6, 2017
I hate you ? was on 10.3.3 before hours now i'm on 11.1.2
— Elie Freigy (@elie1fr) December 6, 2017
More recently, semi-jailbreak tool Houdini for iOS 10.3.2 was released, allowing iOS device owners to install jailbreak tweaks without ever needing to jailbreak their devices.
